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    I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte
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    list_of_values doesn't have to be a list; it can be set, tuple, dictionary, numpy array, pandas Series, generator, range etc and isin() and query() will still work
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    The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings Other than that I think the only difference is speed: it looks like it's a little faster the first way Try it yourself with timeit timeit () or preferably timeit repeat ()
  • Python: list of lists - Stack Overflow
    The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list
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    If your list of lists comes from a nested list comprehension, the problem can be solved more simply directly by fixing the comprehension; please see How can I get a flat result from a list comprehension instead of a nested list? The most popular solutions here generally only flatten one "level" of the nested list See Flatten an irregular (arbitrarily nested) list of lists for solutions that
  • Most efficient way to find if a value exists within a C# List
    In C# if I have a List of type bool What is the fastest way to determine if the list contains a true value? I don’t need to know how many or where the true value is I just need to know if one e
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    The second action taken was to revert the accepted answer to its state before it was partway modified to address "determine if all elements in one list are in a second list"
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    A list of lists would essentially represent a tree structure, where each branch would constitute the same type as its parent, and its leaf nodes would represent values




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