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- operators - What does =~ do in Perl? - Stack Overflow
51 I guess the tag is a variable, and it is checking for 9eaf - but does this exist in Perl? What is the "=~" sign doing here and what are the " " characters before and after 9eaf doing?
- What is the meaning of @_ in Perl? - Stack Overflow
128 perldoc perlvar is the first place to check for any special-named Perl variable info Quoting: @_: Within a subroutine the array @_ contains the parameters passed to that subroutine More details can be found in perldoc perlsub (Perl subroutines) linked from the perlvar: Any arguments passed in show up in the array @_
- operators - What is the difference between || and or in Perl . . .
53 From Perl documentation: OR List operators On the right side of a list operator, it has very low precedence, such that it controls all comma-separated expressions found there
- Whats the use of lt; gt; in Perl? - Stack Overflow
What's the use of <> in Perl How to use it ? If we simply write <>; and while (<>) what is that the program doing in both cases?
- How can I parse command-line arguments in a Perl program?
I'm working on a Perl script How can I parse command line parameters given to it? Example: script pl "string1" "string2"
- What does the - gt; arrow do in Perl? - Stack Overflow
7 Perl arrow operator has one other use: Class−>method invokes subroutine method in package Class though it's completely different than your code sample Only including it for completeness for the question in the title
- How does double arrow (= gt;) operator work in Perl? - Stack Overflow
The => operator in perl is basically the same as comma The only difference is that if there's an unquoted word on the left, it's treated like a quoted word So you could have written Martin => 28 which would be the same as 'Martin', 28 You can make a hash from any even-length list, which is all you're doing in your example Your Readonly example is taking advantage of Perl's flexibility with
- How do I perform a Perl substitution on a string while keeping the . . .
In Perl, what is a good way to perform a replacement on a string using a regular expression and store the value in a different variable, without changing the original? I usually just copy the string to a new variable then bind it to the s regex that does the replacement on the new string, but I was wondering if there is a better way to do this?
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